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Expand & simplify 4 ( 2 g 3 ) − 5 ( 4 g − 4 )

Expand & simplify 5(g+2)−4(g−5) Get the answers you need, now! aaliyahgayle2626 aaliyahgayle2626 05.11.2019 Math Secondary School answered Expand & simplify 5(g+2)−4(g−5) 1 See answer aaliyahgayle2626 is waiting for your help. Add your answer and earn points

Expand & simplify 5(g+2)−4(g−5) - Brainly

  1. This calculator can be used to expand and simplify any polynomial expression
  2. Correct answer to the question Expand & simplify 4 ( g + 3 ) − 4 ( g + 6 ) - e-eduanswers.co
  3. How do you simplify (5 p − 3 q) (5 r − 6) + 4 (6 + 4 r) First expand-g+2(3+g)=-4(g+1) -g+2(3+g)=-4(g+1) One solution was found : g = -2 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 12(1-3g)+8(g+f) 1 2 (1 − 3 g) + 8 (g + f).
  4. 10(g+5)=2(g+9) One solution was found : g = -4 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :.
  5. Free simplify calculator - simplify algebraic expressions step-by-step This website uses cookies to ensure you get the best experience. By using this website, you agree to our Cookie Policy
  6. Expand & simplify 4 ( g + 2 ) − 2 ( g − 6 ) Answers. Answer from: xxgissellexx. 2g+20. Step-by-step explanation: multiply the 4 by whats in the parenthasis. and multiply the negative 2 by whats in the parenthasis. combine the like terms. Answer from: alexandrafaber93061. 4(2z + 5) Step-by-step explanation:.
  7. Need Some Help Please Given the expression: 4x10 − 64x2 Part A: Rewrite the expression by factoring out the g reatest common factor. (4 points) Part B: Factor the entire expression completely

Expand and Simplify Polynomials Calculato

Solution Steps. 6 ( g + 4 ) + 5 ( g + 3 ) 6 ( g + 4) + 5 ( g + 3) Use the distributive property to multiply 6 by g+4. Use the distributive property to multiply 6 by g + 4. 6g+24+5\left (g+3\right) 6 g + 2 4 + 5 ( g + 3) Use the distributive property to multiply 5 by g+3 E.g. (x + 5)(x − 1) = x 2 + 5x − x − 5 = x 2 + 4x − 5 Remember: expressions with three terms like x 2 + 4x − 5 are known as trinomials. An expression that contains more than two terms and includes variables and coefficients is called a polynomial

2 2a. Expand [3 marks] (x−2)4 and simplify your result. Markscheme evidence of expanding M1 e.g. A2 N2 [3 marks] (x−2)4=x4+4x3(−2)+6x2(−2)2+4x(−2)3+(−2)4 (x−2)4=x4−8x3+24x2−32x+16 2b. Find the term in [3 marks] in. Markscheme finding coefficients (A1)(A1) term is A1 N3 [3 marks] x3 (3x+4)(x−2) Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more Given #g(x)=5/(x−3)#, evaluate and simplify: #(g(5+h)−g(5))/h =#? Precalculus. 2 Answer Expand and simplify (x − 4) (2x + 3y)^2. Rewrite (x − 4) (2x + 3y)2 as (x - 4) (2x + 3y) (2x + 3y) Multiply out the first two brackets to give - (2x 2 + 3xy - 8x 2 - 12y) (2x + 3y) Multiply out the remaining brackets4x 3 + 6x 2 y - 16x 2 - 24xy + 24xy + 6x 2 y + 9xy 2 - 24xy - 36y 2. Simply what's left... 4x2 + 12x2y + 9xy2 - 16x2.

Expand & simplify 4 ( g + 3 ) − 4 ( g + 6

The equation of the height of the arrow with respect to time is y= -4.9x2 + 48x, where y is the height of the arrow in meters above Andrew's bow and 2 is the time in seconds since Andrew shot the arrow. Find how long it takes the arrow to come back to a height even with his bow height. arrow left 1. Simplify the expression: 4√18+5√32 A.45√2 B.32√2 C.116√2 D.9√50 2. Simplify the expression: 7√5-3√80 A.-5√5 B.-4√75 C.-5 D.4√-75 3. Simplify the expression: √21(√3+√14) A.9√7-49√6 B.2√6+√3 View Homework Help - Advanced Functions Unit One from MHF 4U at Independent Learning Center (alternative). Unit One 1. Expand and simplify the following powers. −5 a7 b2 ¿(4 a3 b6 )0 A) 2 ( 3 a 8 Solving Linear Equations Solve for the variable in each of the following. Simplify your answers. 49) A −5 =13 50) C +6 = −2 51) 3(x +2) = 4 x +9 Working with Formula Textbook solution for Trigonometry (MindTap Course List) 8th Edition Charles P. McKeague Chapter A.3 Problem 47PS. We have step-by-step solutions for your textbooks written by Bartleby experts! Let f ( x ) = 2 x − 5 and g ( x ) = x 2 + 3 x + 4

View Exponentials Review - Chapter 3.pdf from MATH 4U at Sheridan College. - Chapter 3 pages 94 - 115 (Covers Lessons 3A to 3G) ( ± )4 = 4 ± 2 + 4 Example 1 Expand and simplify. ( + )( − ) = 4 Click here to get an answer to your question ️ Expand and simplify (3x-2)^2 emma6825 emma6825 11/17/2020 Mathematics High School Expand and simplify (3x-2)^2 1 See answer can you please tell me what you mean by expand and simplify? emma6825 is waiting for your help. Add your answer and earn points 1. (-10x^3 + 30x -20) divided by (-5x+5)? a)2x^2-2x+4**** b)-2x^2-2x-4 c)-2x^2+2x+4 d)2x^2+2x-4 2.The width, w, of a rectangular playground is x + 3. The area of the garden is x^3 - 7x + 6. What is an expression for the length of . Mat View Unit 1 MHF4UC ILC.docx from MATH MHF4UC at Indipendent Learning Centre. Task 1 1) Expand and simplify a) 4 3 2 7 2 3 6 0 ( 3 a b ) ( 5 a b ) ( 4 a b ) 2 4a 3b b) ( ) x 2a y = = ( 9 a 8 b 6 )( 5 Expand & simplify 4 ( g + 3 ) − 4 ( g + 6 ) 1 See answer shakirahassan934 is waiting for your help. Add your answer and earn points. rllucasne rllucasne Answer:-12. Step-by-step explanation: New questions in Mathematics. Helpppp 3x + 10 3x + 2 x = [?] Clock #2: A clock has a radius of 6 inches. The center is 14.5 inches below the ceiling

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Solve 5(g+5)+2(g+4) Microsoft Math Solve

Let us simplify (reduce) this block diagram using the block diagram reduction rules. Step 1 − Use Rule 1 for blocks G 1 and G 2. Use Rule 2 for blocks G 3 and G 4. The modified block diagram is shown in the following figure. Step 2 − Use Rule 3 for blocks G 1 G 2 and H 1. Use Rule 4 for shifting take-off point after the block G 5 Let f(x)=x^2-4f ( x ) = x ^2 − 4 and g(x)=3x-5g ( x ) = 3 x − 5. Find and simplify ( f ∘ g ) ( x ). Type up your work and the answer Quadratics. A polynomial is an algebraic expression usually containing one variable. e.g. p 3 + 3p 2 + 2p − 1. A quadratic is a polynomial expression whose highest power is 2. e.g. x 2 + 2x + 1 Quadratics are usually obtained by finding the product of two bracketed expressions. There are several similar ways of expanding brackets, two of which are given below

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2 3 2 5 √ ∙ 3 4) Expand and Simplify; a) (1+ 2 ) 2 −(2−1 ) 2 b) ( T 5 2− U 5 2)( T 5 2+ U 5 2) 5) Factor completely: a) 27 3−12 b) 27 6 3 −125 (factor as a difference of cubes) c) 2 T 1 3( T−2) 2 3−5 T 4 3( T−2)− 1 3 d) (4+ 9 ) 2 −(4−9 ) 2 e) 3− 3 2−6 6) Perform the operation indicated and simplify all solutions. 2. Simplify radical expression sqrt 50 5 sqrt ^2*** 2 sqrt ^5 5 sqrt ^10 5 2. Simplify the radical expression sqrt 56x^2 28x 2x sqrt 14*** 2x sqrt 7 sqrt 14x2 3. Simplify the radical expression. sqrt 490y^5w^6 2 sqr − 307 1024 − 2247 1024 ⁢ t + 1575 1024 ⁢ t 2 + 5075 1024 ⁢ t 3 (13) To selectively prevent expansions of subexpressions, it is frequently useful to use indets , to get subexpressions of certain type, and pass the operands of its output as extra arguments to expand

Expand & simplify 4 ( g + 2 ) − 2 ( g − 6

  1. us, times, and divide) that they tell me to, in the order that they tell me to. ( f + g ) ( x) = f ( x) + g ( x) = [3 x + 2] + [4 - 5 x] = 3 x + 2 + 4 - 5 x. = 3 x - 5 x + 2 + 4. = -2 x + 6. ( f - g ) ( x) = f ( x) - g ( x
  2. The ability to set up and simplify difference quotients is essential for calculus students. It is from the difference quotient that the elementary formulas for derivatives are developed. (5+h)=+-3(5h)2 4(5+-h)5 = 3(25++10hh2)−−−204h5 2=75++30h3h−−−204h5=++3h26h502 V. The difference quotient is so named because the operations.
  3. ator : 9 9 • 2 9 = — = ————— 1 2 Adding fractions that have a.
  4. Expand and simplify. a) 2( 2 − 2 + 4) b) −( + 1) − 2( + 2) c) (2 + 2)(− + 1) Math MBF 3C. Comments (1) Topic; expanding and simplifying. Expert Tutor. Comments (0) Answer & Explanation. Solved by verified expert. Rated Helpful Answer at the explanation.
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expand and simplify 2(3x+4)-3(x-2) - Brainly

Solve 6(g+4)+5(g+3) Microsoft Math Solve

3 2 −3 = −3 −3 = −6. The right side of the equation is equal to 4 ⋅ − 3 2 = 2 ⋅(−3) = −6. Since the left side equals the right side, we know we have found the number that solves the equation 2−3 = 4. Example 2 (4 minutes) Solve the linear equation 3 5 −21 = 15 Exercise 2.4.1. Using the definition, determine whether the function f(x) = {2x + 1, if x < 1 2, if x = 1 − x + 4, if x > 1 is continuous at x = 1. If the function is not continuous at 1, indicate the condition for continuity at a point that fails to hold. Hint. Check each condition of the definition. Answer

Expand and Simplify - GCSE Maths - Lesson, Examples

3.2 Adding up the two equivalent fractions. Add the two equivalent fractions which now have a common denominator. Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible: g • 7 - (3) 7g - 3 ——————————— = —————— 7 7 If you multiply binomials often enough you may notice a pattern. Notice that the first term in the result is the product of the first terms in each binomial. The second and third terms are the product of multiplying the two outer terms and then the two inner terms. And the last term results from multiplying the two last terms,. We abbreviate First, Outer, Inner, Last as FOIL (x - 3) Is a number, just 4, 10, 258, and so on. In the same way that 3^2 = 3 * 3, (x - 3)^2 = (x - 3) * (x-3), or (x - 3)(x-3). From there, we just multiply each term in the second set of parentheses by each term in the first set, and add these p.. Dividing exponential expressions : 5.1 x1 divided by x2 = x(1 - 2) = x(-1) = 1/x1 = 1/x Expand and Condense Logarithms DRAFT. 11 hours ago. by marialambert. Played 0 times. 0. 11th - 12th grade . Mathematics.

11) −(1 − 5x) 12) −4(7r + 7) -1- ©q 2KRubtnax ESzoBfetYw3aGrje n 3LZLECF.j X 6AkldlM SrLi5gWhdtqsZ FrheCsBetr PvHerdn.z R 5M7asd2eh rw CiXtxhT JIgnMfXiEn4iOtFeW ZAzlVgfeDbZrUa1 o13.c Worksheet by Kuta Software LL (Matching Type) Given f(x)=x+2 and g(x)=x2−4 match the expression to its simplification operation. x - 2 Answer 1 x2 + x - 2 Answer 2 1/x-2 Answer 3 -x2 + - 857 johnivansedotes johnivansedotes 3. Simplify the given function . Read the details on another example of addition on function in brainly.ph/question/1813217 Correct answer - Expand and simplify 3(2x + 1) + 2(x + 4) Step by step pl

In mathematics, function composition is an operation that takes two functions f and g and produces a function h such that h(x) = g(f(x)).In this operation, the function g is applied to the result of applying the function f to x.That is, the functions f : X → Y and g : Y → Z are composed to yield a function that maps x in X to g(f(x)) in Z.. Intuitively, if z is a function of y, and y is a. Textbook solution for Essential Calculus: Early Transcendentals 2nd Edition James Stewart Chapter T Problem 6ADT. We have step-by-step solutions for your textbooks written by Bartleby experts

Solve 4(f+3)+3(f+3) Microsoft Math Solve

simplify g^ {4/7}*g^ {3/7} \square! \square! . Get step-by-step solutions from expert tutors as fast as 15-30 minutes. Your first 5 questions are on us QuickMath will automatically answer the most common problems in algebra, equations and calculus faced by high-school and college students. The algebra section allows you to expand, factor or simplify virtually any expression you choose. It also has commands for splitting fractions into partial fractions, combining several fractions into one and.

Expand 4(3. x. − 2) 4(3. x. − 2) = 12. x. − 8 Multiply everything inside the bracket by the 4 outside the bracket . Example 2 . Expand and simplify 3(x + 5) − 4(2. x + 3) 3(x + 5) − 4(2. x + 3) = 3. x + 15 − 8. x - 12 = 3 − 5. x. 1 . Expand each set of brackets separately by multiplying (x + 5) by 3 and (2. x + 3) by −4 . 2. e) 2×3 f) 4 ×5 g) −2×7 h) 3×−2 i) 2 × j) 3 ×2 k) −2 × l) −3 ×4 m) −2 ×(− ) n) −3 × o) − ×(−2 ) p) 3 ×(−2) q) (− ) r) (−2 ) s) 2 × t) ×(−3 ) EXERCISE 2 Simplify the following: a) 2×5 +3 ×4 b) 5×3 −2 × c) 3× +2 ×4 g) (2 G+1)( G−5) h) (4 T−7)(4 T+7) i) (3 T+2)2 j) (2 U−7) 3. Multiply out and simplify :- a) ( U−1)( U2+2 U+1) b) ( I+3)( I2+3 I−2) c) ( T+3)( T2+ T−2) d) ( P−2)(3 P2−3 P−2) e) ( T−5)(2 T2+3 T+6) f) (2 G+3)(3 G2+4 G−6) g) (5 I+3)2(3 I−2) h) ( G2+4 G+1)2 i) (2 T2−6 T−3)2 j) T( T+2)2 4. Expand the brackets and simplify. −3a 2(3−b) = −9a 2+3a b Example Expand (x+5)x. Here, the brackets appear first, but the prin-ciple is the same. Both terms inside must be multiplied by the x outside: (x+5)x = x +5x Exercises 1. Remove the brackets from the following expressions. a) 5(x+4) b) 2(y −3) c) 4(3− a) d) x(2+x) e) p(q +3) f) −3(2+a) g) s(t− s) h) −2(b.

Given g(x)=5/(x−3), evaluate and simplify: (g(5+h)−g(5))/h

16x 4 − 0.09818x 2 + 3.0593x − 23.77365 = 0. 5) A quartic equation solver to the rescue: Four roots were generated, two of which are imaginary. One root is negative and the fourth root (a positive value) is our answer for 'x.' It is 1.066 (rounded off). 6) Determine moles of H 2, then grams Coordinate Geometry 8 200 Negative gradients: m < 0 Positive gradients: m > 0 Chapter Contents 8:01 The distance between two points 8:02 The midpoint of an interval 8:03 The gradient of a line 8:04 Graphing straight lines 8:05 The gradient-intercept form of a straight line: y = mx + c Investigation: What does y = mx + c tell us? 8:06 The equation of a straight line, given poin Describe the transformation of f (x) = log 2 x represented by the graph of g. Question 6. Let f (x) = 2x 3 − 4x 2 + 8x− 1, g (x) = 2x − 3x 4 − 6x 3 + 5, and h (x) = −7 + x 2 + x. Order the following functions from least degree to greatest degree. Question 7. Write an exponential model that represents each data set

Algebra (0th Edition) Edit edition. Problem 20E from Chapter 11.7: Expand and simplify the expression.(x − 1)4(x + 1)4. Get solution Factorise completely 7k2 − 22k + 3. [1] 2. Expand and simplify (x + 2)(3x − 8) − 2x(y + 4) − 3y. [2] 3. Write the area of the trapezium as both a factorised and expanded expression. [3] 2m. Solve: Start with: S + A < 9. A = S + 3, so: S + (S + 3) < 9. Simplify: 2S + 3 < 9. Subtract 3 from both sides: 2S < 9 − 3. Simplify: 2S < 6. Divide both sides by 2: S < 3. Sam scored less than 3 goals, which means that Sam could have scored 0, 1 or 2 goals. Alex scored 3 more goals than Sam did, so Alex could have scored 3, 4, or 5 goals 18 x 3 y −3 x y − 36 x y 2 −3 x y 18 x 3 y −3 x y − 36 x y 2 −3 x y: Simplify. −6 x 2 + 12 y −6 x 2 + 12 y: Try It 5.75. Find the quotient: (32 a 2 b Use synthetic division to find the quotient and remainder when 4 x 3 + 5 x 2 − 5 x + 3 4 x 3 + 5 x 2. (a) y = x4 (b) g(s)=s−2 (c) h(t)=t3/4 Example 3: Find the derivative of each of the following functions with respect to x: (a) y = 1 x5 (b) g(x)=3 √ x (c) h(x)= 1 5 √ x! The constant multiple rule: Let c be a constant andf(x) be a differentiable function. • (cf(x)) = c(f(x)). • d dx! cf(x) = c d dx! f(x)

Page 5 (Section 4.1) 4.1 Homework Problems 1. Use a calculator to find each value to four decimal places. (a) 5 (b) 3 7 (c) π 2− 5.3 (d) e2 (e) e−2 (f) −e 0.25 (g) π−1 2. Simplify each expression without using a calculator Suppose that f(2) = −3, g(2) = 5, f '(2) = −2, and g'(2) = 4. Find h'(2)? h(x) = g(x) / 1 + f(x) Calculus Basic Differentiation Rules Chain Rul 2.2 Evaluate, Simplify, and Translate Expressions; 2.3 Solving Equations Using the Subtraction and Addition Properties of Equality; 2.4 Find Multiples and Factors; 2.5 Prime Factorization and the Least Common Multipl Convert the following integral to cylindrical coordinates and evaluate. ˆ 2 −2 ˆ √ 4−x2 − √ 4−x2 ˆ 16 (x2+y 2) 2 x 2 dz dy dx Textbook solution for Intermediate Algebra 10th Edition Jerome E. Kaufmann Chapter A Problem 19PE. We have step-by-step solutions for your textbooks written by Bartleby experts

Identify the asymptote of the function g(x) = 20.5x − 2. y=-2 Identify the transformed function that represents f(x) = ln x stretched vertically by a factor of 3, reflected across the x-axis, and shifted 7 units to the right e.g. 3 + x, 5y − 4x 2, x 2 − 3x + 5: coefficient: the number part of a particular term e.g. in the expression 5x 2 − x + 3, the coefficient of x 2 is 5 and the coefficient of x is -1: like terms: terms which have exactly the same letters in e.g. 2x and −3x are like terms, but 5y and 3y 2 are not like term Try to further simplify. Verificar expandir\:(2x-5)(3x+6) expandir\:(4x^2-3)(3x+1) expandir\:(x^2+3y)^3; expand-calculator. Expand ( x^{2}+3x−4) ( x^{2}+5x−1) pt. Related Symbolab blog posts. Middle School Math Solutions - Equation Calculator. Welcome to our new Getting Started math solutions series. Over the next few weeks, we'll. 2 x ±− = M1 8.45, 3.55 A1 A1 20 (a) 2 3 − A1 (b) 2 2 1 1 5 x x − M1 15− x2 A1 (c) y 5 x y − = exchange letters, rearrange to y = M1 1 5 f() 1 x x − = − A1 −3 −2 −1 1 2 3 −2 2 4 6 8 10 12 14 x Exercise 2.5.1. Using the definition, determine whether the function f(x) = {2x + 1, if x < 1 2, if x = 1 − x + 4, if x > 1 is continuous at x = 1. If the function is not continuous at 1, indicate the condition for continuity at a point that fails to hold. Hint. Check each condition of the definition. Answer

The answer is (3x^2-3)*(2x^2 + 3x + 5) + (x^3 − 3x)*(4x+3), which simplifies to 10x^4+12x^3-3x^2-18x-15. According to the product rule, ( f ⋅ g ) ′ = f ′ ⋅ g + f ⋅ g ′ This just means that when you differentiate a product, you do derivative of the first, leave second alone, plus derivative of the second, leave the first alone. So the first would be (x^3 − 3x) and the second. Learn with Tiger how to do 0.25a^6b^2−0.6a^4b^4+0.36a^2b^6 fractions in a clear and easy way : Equivalent Fractions,Least Common Denominator, Reducing (Simplifying) Fractions Tiger Algebra Solve

1) Subtract the first equation from the second equation: 2C(s) + O 2 (g) + 4H 2 (g) − [2C(s) + O 2 (g)] ---> 2CH 3. 2) Simplify: 4H 2 (g) ---> 2CH 3. 3) Rearrange: 2CO(g) + 4H 2 (g) ---> 2CH 3. 4) Divide through by 2: CO(g) + 2H 2 (g) ---> CH 3. Solution #2: This is the usual way the ChemTeam uses to solve Hess' Law problems. 1) Do these. www.justmaths.co.uk Simplify / Expand & Simplify (F) - Version 3 January 2016 (d) ì6 ì2 [1] 12. To fill in a block, you must add the values on the two blocks directly below it 3.4.2 Recognize simple linear factors in a rational function. Next, we perform partial fraction decomposition on 3 x + 5 x 2 − 4 = 3 x + 5 (x + 2) (x Rewrite in terms of x and simplify. Substituting back into the original integral and simplifying gives

Double-Angle and Half-Angle Formulas. a 2 depend on which quadrant a 2 lies in. For cos. a 2 any formula can be used to solve for the exact value. π 8. π 8 is half of π 4 and in the first quadrant. a = − 4 5 and 3 π 2 ≤ a < 2 π. a, which would be 3 5 because a is in the 4 t h quadrant. 2 a for a from the previous problem 3.1 The Power Rule 57 Now without much trouble we can verify the formula for negative integers. First let's look at an example: EXAMPLE3.1.2 Find the derivative of y= x−3.Using the formula, y′ = −3x−3−1 = −3x−4. Here is the general computation Math 145 Sec S08N01 - Final Exam Apr 21 2008 Question 4: (a)[5 points] Put the quadratic function f(x) = −2x2 −4x−5 into standard form by completing the square. State the vertex and axis of symmetry of the graph of f(x) y=-x^2-x+6 expanded in the simplest form PREMISES y=(2-x)(3+x) in the expanded and simplified form CALCULATIONS y=(2-x)(3+x) in the expanded and simplified form y=(2×3)+2x-3x-x^2 y=6+(2x-3x)-x^2 y=6+(-x)-x^2 y=6-x-x^2 [Flip the right side of the e.. This expression relates directly to the geometry of the rectangle-as-squares jigsaw as follows: 2 orange squares (16 x 16) ; 1 blue square (13 x 13) ; 4 red squares (3 x 3) ; 3 yellow squares (1 x 1) . Since the numbers always reduce, that is, the size of the remaining rectangle left over will always have one side smaller than the starting rectangle, then the process will always stop with a.