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# Expand & simplify 4 ( 2 g 3 ) ŌłÆ 5 ( 4 g ŌłÆ 4 )

### Expand & simplify 5(g+2)ŌłÆ4(gŌłÆ5) - Brainly

1. This calculator can be used to expand and simplify any polynomial expression
2. ĒĀĮĒ▒Ź Correct answer to the question Expand & simplify 4 ( g + 3 ) ŌłÆ 4 ( g + 6 ) - e-eduanswers.co
3. How do you simplify (5 p ŌłÆ 3 q) (5 r ŌłÆ 6) + 4 (6 + 4 r) First expand-g+2(3+g)=-4(g+1) -g+2(3+g)=-4(g+1) One solution was found : g = -2 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 12(1-3g)+8(g+f) 1 2 (1 ŌłÆ 3 g) + 8 (g + f).
4. 10(g+5)=2(g+9) One solution was found : g = -4 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :.
5. Free simplify calculator - simplify algebraic expressions step-by-step This website uses cookies to ensure you get the best experience. By using this website, you agree to our Cookie Policy
6. Expand & simplify 4 ( g + 2 ) ŌłÆ 2 ( g ŌłÆ 6 ) Answers. Answer from: xxgissellexx. 2g+20. Step-by-step explanation: multiply the 4 by whats in the parenthasis. and multiply the negative 2 by whats in the parenthasis. combine the like terms. Answer from: alexandrafaber93061. 4(2z + 5) Step-by-step explanation:.
7. Need Some Help Please Given the expression: 4x10 ŌłÆ 64x2 Part A: Rewrite the expression by factoring out the g reatest common factor. (4 points) Part B: Factor the entire expression completely

### Expand and Simplify Polynomials Calculato

Solution Steps. 6 ( g + 4 ) + 5 ( g + 3 ) 6 ( g + 4) + 5 ( g + 3) Use the distributive property to multiply 6 by g+4. Use the distributive property to multiply 6 by g + 4. 6g+24+5\left (g+3\right) 6 g + 2 4 + 5 ( g + 3) Use the distributive property to multiply 5 by g+3 E.g. (x + 5)(x ŌłÆ 1) = x 2 + 5x ŌłÆ x ŌłÆ 5 = x 2 + 4x ŌłÆ 5 Remember: expressions with three terms like x 2 + 4x ŌłÆ 5 are known as trinomials. An expression that contains more than two terms and includes variables and coefficients is called a polynomial

2 2a. Expand [3 marks] (xŌłÆ2)4 and simplify your result. Markscheme evidence of expanding M1 e.g. A2 N2 [3 marks] (xŌłÆ2)4=x4+4x3(ŌłÆ2)+6x2(ŌłÆ2)2+4x(ŌłÆ2)3+(ŌłÆ2)4 (xŌłÆ2)4=x4ŌłÆ8x3+24x2ŌłÆ32x+16 2b. Find the term in [3 marks] in. Markscheme finding coefficients (A1)(A1) term is A1 N3 [3 marks] x3 (3x+4)(xŌłÆ2) Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more Given #g(x)=5/(xŌłÆ3)#, evaluate and simplify: #(g(5+h)ŌłÆg(5))/h =#? Precalculus. 2 Answer Expand and simplify (x ŌłÆ 4) (2x + 3y)^2. Rewrite (x ŌłÆ 4) (2x + 3y)2 as (x - 4) (2x + 3y) (2x + 3y) Multiply out the first two brackets to give - (2x 2 + 3xy - 8x 2 - 12y) (2x + 3y) Multiply out the remaining brackets4x 3 + 6x 2 y - 16x 2 - 24xy + 24xy + 6x 2 y + 9xy 2 - 24xy - 36y 2. Simply what's left... 4x2 + 12x2y + 9xy2 - 16x2.

### Expand & simplify 4 ( g + 3 ) ŌłÆ 4 ( g + 6

• Expanding Brackets Video 13 on wwwcorbettmathscom Question 1 Expand the from SOCI 607 at University of Delawar
• 7.2 Solve : -5 = 0 This equation has no solution. A a non-zero constant never equals zero. Solving a Single Variable Equation : 7.3 Solve : 2g-3 = 0 Add 3 to both sides of the equation : 2g = 3 Divide both sides of the equation by 2: g = 3/2 = 1.500. One solution was found : g = 3/2 = 1.50
• C: Manipulate Expressions (III) 1) Expand and simplify (ĒĀĄĒ▒Ī+5)(ĒĀĄĒ▒ĪŌłÆ4) 2) Factorise 2+17 +60 3) Factorise 2ŌłÆ144 4) Factorise 2 2ŌłÆ7 ŌłÆ15 5) Simplify 5 4 3├Ś 2 6) Simplify 45 ├ś 6 ├Ö8 5 ├ś ├Ö2 7) Factorise 4 2ŌłÆ1 8) Factorise 2 2+3 +1 9) Simplify (ĒĀĄĒ▒Ü3)
• Textbook solution for Essential Calculus: Early Transcendentals 2nd Edition James Stewart Chapter T Problem 3ADT. We have step-by-step solutions for your textbooks written by Bartleby experts
• Q1. Solve the following: (i) 4 ŌłÆ x Ōēż 13 (ii) 2(x ŌłÆ 6) + 3x Ōēż 8 (iii) x 2 + x 3 = 5. Q2. Factorise completely (i) 3x ŌłÆ 6y + ax ŌłÆ 2ay (ii) p 2 ŌłÆ 1 (iii) x 2 ŌłÆ x ŌłÆ 12 (iv) 2x 2 ŌłÆ 5x ŌłÆ 7. Q3. Expand and simplify (i) (2k ŌłÆ 3)(k ŌłÆ 2) Q4 For the functions. f(x) = 7x + 4 , h(x) = 10 x ŌłÆ 3 and g(x) = 3x ŌłÆ 2 (a) Evaluate (i.
• Simplify eachterm Ōłł parentheses:2 p 2 (1 ŌłÆ 4 p 3 + 5 p 4) b. 10 g 2 h 2 + 5 g 3 h ŌłÆ 15 g 4 h 5 (2 points) Findthe greatestcommon factor: GCF = 5 g 2 h Factor out the GCF. (Write theGCF first .Then, Ōłł parentheses ,divideeachtermby theGCF .) 5 g 2 h (10 g 2 h 2 5 g 2 h + 5 g 3 h 5 g 2 h + ŌłÆ 15 g 4 h 5 g 2 h) Simplify eachterm Ōłł.

The equation of the height of the arrow with respect to time is y= -4.9x2 + 48x, where y is the height of the arrow in meters above Andrew's bow and 2 is the time in seconds since Andrew shot the arrow. Find how long it takes the arrow to come back to a height even with his bow height. arrow left 1. Simplify the expression: 4ŌłÜ18+5ŌłÜ32 A.45ŌłÜ2 B.32ŌłÜ2 C.116ŌłÜ2 D.9ŌłÜ50 2. Simplify the expression: 7ŌłÜ5-3ŌłÜ80 A.-5ŌłÜ5 B.-4ŌłÜ75 C.-5 D.4ŌłÜ-75 3. Simplify the expression: ŌłÜ21(ŌłÜ3+ŌłÜ14) A.9ŌłÜ7-49ŌłÜ6 B.2ŌłÜ6+ŌłÜ3 View Homework Help - Advanced Functions Unit One from MHF 4U at Independent Learning Center (alternative). Unit One 1. Expand and simplify the following powers. ŌłÆ5 a7 b2 ┬┐(4 a3 b6 )0 A) 2 ( 3 a 8 Solving Linear Equations Solve for the variable in each of the following. Simplify your answers. 49) A ŌłÆ5 =13 50) C +6 = ŌłÆ2 51) 3(x +2) = 4 x +9 Working with Formula Textbook solution for Trigonometry (MindTap Course List) 8th Edition Charles P. McKeague Chapter A.3 Problem 47PS. We have step-by-step solutions for your textbooks written by Bartleby experts! Let f ( x ) = 2 x ŌłÆ 5 and g ( x ) = x 2 + 3 x + 4

### Solve -3g+2f+g-4f Microsoft Math Solve

• 5. Expand and simplify: (x ŌłÆ 4) 2. Show answer = x 2 ŌłÆ 8x + 16. 6. Expand and simplify: (2x + 5) 2. Show answer = 4x 2 + 20x + 25. 3) Expanding triple brackets. To expand triple brackets we first multiply the first two brackets together. We then multiply every term in this new expression by every term in the third bracket
• Expand the brackets and simplify ( )2 2 5 ŌłÆ 2 A:4 5 + 2 2 B: 12 ŌłÆ 4 10 C: 8ŌłÆ 4 10 D: 2 10 ŌłÆ 2 E: None of these Question 47 Rationalise and simplify 3 4 5 A: 2 B: 3 6 C: 6 D: 3 6 E: None of these Question 48 If 2 x = 1 3 y = 2 and 4 z = 3 evaluate x ├Ę y + z A: 2 1 1 B: 7 3 C: 12 1 1 D: 4 3 E: None of these Question 49 Expand and.
• Example 4 Expand and simplify (x ŌłÆ 5)(2x + 3) (x ŌłÆ 5)(2x + 3) = x(2x + 3) ŌłÆ 5(2x + 3) = 2. x. 2 + 3. x. ŌłÆ 10. x. ŌłÆ 15 = 2. x. 2. ŌłÆ 7. x. ŌłÆ 15 . 1 . Expand the brackets by multiplying (2. x + 3) by . x. and (2. x + 3) by ŌłÆ5 . 2 Simplify by collecting like terms: 3x ŌłÆ 10x = ŌłÆ7x. Practice : 1 Expand. a 3(2x 2ŌłÆ 1) b ŌłÆ2(5pq.
• Expand and simplify 3 (2 a + 5) + 5 (a ŌłÆ 2) 3\left(2a+5\right)+5\left(a-2\right) 3 (2 a + 5) + 5 (a ŌłÆ 2) answer choices 11 a + 5 11a+5 1 1 a + 5
• k (2x ŌłÆ 7)2 l (4x ŌłÆ 3y)2 Extend 9 Expand and simplify (x + 3)┬▓ + (x ŌłÆ 4)┬▓ 10 Expand and simplify. a 12 xx xx ┬¦ ┬Ę┬¦ ┬Ę ┬© ┬Ė┬© ┬Ė ┬®┬® ┬╣┬╣ b 2 1 x x ┬¦┬Ę ┬©┬Ė ┬®┬╣ Watch out! When multiplying (or dividing) positive and negative numbers, if the signs are the same the answer is '+'; if the signs are different the answer is '-'
• CHAPTER 7 FACTORISING ALGEBRAIC EXPRESSIONS 177 Factorise the following completely. a 5x + 15 y b ŌłÆ3m ŌłÆ m2 c 6xy ŌłÆ 2 x d 15 p ŌłÆ 20 q e 15 pq ŌłÆ 20 q f 12 st 2 + 15 st g ŌłÆ18 xy ŌłÆ 6 x h at ŌłÆ at 2 i 7x2y + xy j a2 + ab Factorise each of the following. a a2 + ab + 3 a b xy ŌłÆ 3 x2 + 2 x c 12 st ŌłÆ 4 t3 + 8 t d 36 ŌłÆ 12 ab + 18 b e 3ab ŌłÆ 9 a2b + 12 ab 2 + a2b2 f 4m ŌłÆ 8 n ŌłÆ.
• How do I expand and simplify the following (x+5) (x-2) (x+5) (xŌłÆ2) is a product of 2 linear polynomial, and thus a quadratic one. Let us find a,b,c such that: (x+5) (xŌłÆ2)=ax2+bx+c. By solving a system of 3 linear equations: Plug x=0: (x+5) (xŌłÆ2)= (0+5) (0ŌłÆ2)=ŌłÆ10. So, aŌŗģ02+0b+c=ŌłÆ10ŌćÆc=ŌłÆ10

### Solve 5(g+5)+2(g+4) Microsoft Math Solve

• Expand and simplify an expression. The calculator allows you to expand and collapse an expression online , to achieve this, the calculator combines the functions collapse and expand. For example it is possible to expand and reduce the expression following ( 3 x + 1) ( 2 x + 4), The calculator will returns the expression in two forms : expanded.
• = 6x2 + 3x ŌłÆ 18 ŌłÆ 2x2 ŌłÆ 5x + 3 = 3x4 ŌłÆ 5x3 ŌłÆ 3x2 + 9x ŌłÆ 4 = 4 x 2 ŌłÆ 2 x ŌłÆ 15 Pure Math 10 Notes Unit 1: Polynomial
• Systems of equations 1. Solve the system: 5 x ŌłÆ 3 y = 6 4 x ŌłÆ 5 y = 12. \begin {array} {l} {5x-3y = 6} \\ {4x-5y = 12} \end {array} 5xŌłÆ3y = 6 4xŌłÆ5y = 12. . See answer ŌĆ║. Powers and roots 2. Expand for x

Let us simplify (reduce) this block diagram using the block diagram reduction rules. Step 1 ŌłÆ Use Rule 1 for blocks G 1 and G 2. Use Rule 2 for blocks G 3 and G 4. The modified block diagram is shown in the following figure. Step 2 ŌłÆ Use Rule 3 for blocks G 1 G 2 and H 1. Use Rule 4 for shifting take-off point after the block G 5 Let f(x)=x^2-4f ( x ) = x ^2 ŌłÆ 4 and g(x)=3x-5g ( x ) = 3 x ŌłÆ 5. Find and simplify ( f Ōłś g ) ( x ). Type up your work and the answer Quadratics. A polynomial is an algebraic expression usually containing one variable. e.g. p 3 + 3p 2 + 2p ŌłÆ 1. A quadratic is a polynomial expression whose highest power is 2. e.g. x 2 + 2x + 1 Quadratics are usually obtained by finding the product of two bracketed expressions. There are several similar ways of expanding brackets, two of which are given below

### Simplify Calculator - Symbola

2 3 2 5 ŌłÜ ŌłÖ 3 4) Expand and Simplify; a) (1+ 2 ) 2 ŌłÆ(2ŌłÆ1 ) 2 b) ( T 5 2ŌłÆ U 5 2)( T 5 2+ U 5 2) 5) Factor completely: a) 27 3ŌłÆ12 b) 27 6 3 ŌłÆ125 (factor as a difference of cubes) c) 2 T 1 3( TŌłÆ2) 2 3ŌłÆ5 T 4 3( TŌłÆ2)ŌłÆ 1 3 d) (4+ 9 ) 2 ŌłÆ(4ŌłÆ9 ) 2 e) 3ŌłÆ 3 2ŌłÆ6 6) Perform the operation indicated and simplify all solutions. 2. Simplify radical expression sqrt 50 5 sqrt ^2*** 2 sqrt ^5 5 sqrt ^10 5 2. Simplify the radical expression sqrt 56x^2 28x 2x sqrt 14*** 2x sqrt 7 sqrt 14x2 3. Simplify the radical expression. sqrt 490y^5w^6 2 sqr ŌłÆ 307 1024 ŌłÆ 2247 1024 ⁢ t + 1575 1024 ⁢ t 2 + 5075 1024 ⁢ t 3 (13) To selectively prevent expansions of subexpressions, it is frequently useful to use indets , to get subexpressions of certain type, and pass the operands of its output as extra arguments to expand

### Expand & simplify 4 ( g + 2 ) ŌłÆ 2 ( g ŌłÆ 6

1. us, times, and divide) that they tell me to, in the order that they tell me to. ( f + g ) ( x) = f ( x) + g ( x) = [3 x + 2] + [4 - 5 x] = 3 x + 2 + 4 - 5 x. = 3 x - 5 x + 2 + 4. = -2 x + 6. ( f - g ) ( x) = f ( x) - g ( x
2. The ability to set up and simplify difference quotients is essential for calculus students. It is from the difference quotient that the elementary formulas for derivatives are developed. (5+h)=+-3(5h)2 4(5+-h)5 = 3(25++10hh2)ŌłÆŌłÆŌłÆ204h5 2=75++30h3hŌłÆŌłÆŌłÆ204h5=++3h26h502 V. The difference quotient is so named because the operations.
3. ator : 9 9 ŌĆó 2 9 = ŌĆö = ŌĆöŌĆöŌĆöŌĆöŌĆö 1 2 Adding fractions that have a.
4. Expand and simplify. a) 2( 2 ŌłÆ 2 + 4) b) ŌłÆ( + 1) ŌłÆ 2( + 2) c) (2 + 2)(ŌłÆ + 1) Math MBF 3C. Comments (1) Topic; expanding and simplifying. Expert Tutor. Comments (0) Answer & Explanation. Solved by verified expert. Rated Helpful Answer at the explanation.
5. Free equations calculator - solve linear, quadratic, polynomial, radical, exponential and logarithmic equations with all the steps. Type in any equation to get the solution, steps and grap

### expand and simplify 2(3x+4)-3(x-2) - Brainly

• Expand and simplify 4x (x+3) - (2x-3)2. When dealing with such a question, an expansion question, the first part of the equation to look at is the brackets.Looking at the question above, one can see that there are two pairs of brackets - it would be only be plausible to start with the first set.If you are trying to expand a bracket that has.
• Correct answer - Expand and simplify 5(2y+1)^2 -4. 20y┬▓ + 20y + 1. Step-by-step explanation: Given. 5(2y + 1)┬▓ - 4 ŌåÉ expand the factor using FOI
• e the difference between 3a and b + c f the square of x + 2 g the product of x and y ŌłÆ 5 h the square root of 2m + 3 n a What is the cost of 3 books at p cents and 4 pens at q cents each? b What is the change from \$5 (in cents)? Translate the following algebraic expressions into words. a xy b 5 ŌłÆ a c 2p + q d 3m ŌłÆ 2 n e 5(x + y) f (a + b.
• What is the value of the expression (-5) -3? 1. Apply the negative exponents rule: 1 (ŌłÆ5)3 2. Expand the power: 1 (ŌłÆ5)(ŌłÆ5)(ŌłÆ5) 3. Simplify
• Try to further simplify. expand\:(2x-5)(3x+6) expand\:(4x^2-3)(3x+1) expand\:(x^2+3y)^3; expand-calculator. Expand ( x^{2}+3xŌłÆ4) ( x^{2}+5xŌłÆ1) he. Related Symbolab blog posts. Middle School Math Solutions - Equation Calculator. Welcome to our new Getting Started math solutions series. Over the next few weeks, we'll be showing how.
• Textbook solution for Elementary Technical Mathematics 12th Edition Dale Ewen Chapter 2.4 Problem 41E. We have step-by-step solutions for your textbooks written by Bartleby experts! Perform the indicated operations and simplify: ( ŌłÆ 2 3 ) + ( ŌłÆ 5 6 ) + 1 4 + 1 8 | bartleb
• Expand & simplify ( 3 x ŌłÆ 2 ) ( 3 x - 2 ) + ( x + 6 ) ( x ŌłÆ 8 ) Questions in other subjects: World Languages, 23.04.2021 20:50. In Paragraph six of the story behind that was the writer says that Rosa Parks action sparked the Montgomery Bus boycott that followed using evidence from the text as well as infere..

### Solve 6(g+4)+5(g+3) Microsoft Math Solve

3 2 ŌłÆ3 = ŌłÆ3 ŌłÆ3 = ŌłÆ6. The right side of the equation is equal to 4 Ōŗģ ŌłÆ 3 2 = 2 Ōŗģ(ŌłÆ3) = ŌłÆ6. Since the left side equals the right side, we know we have found the number ĒĀĄĒ▒źĒĀĄĒ▒ź that solves the equation 2ĒĀĄĒ▒źĒĀĄĒ▒źŌłÆ3 = 4ĒĀĄĒ▒źĒĀĄĒ▒ź. Example 2 (4 minutes) Solve the linear equation 3 5 ĒĀĄĒ▒źĒĀĄĒ▒źŌłÆ21 = 15 Exercise 2.4.1. Using the definition, determine whether the function f(x) = {2x + 1, if x < 1 2, if x = 1 ŌłÆ x + 4, if x > 1 is continuous at x = 1. If the function is not continuous at 1, indicate the condition for continuity at a point that fails to hold. Hint. Check each condition of the definition. Answer

### Expand and Simplify - GCSE Maths - Lesson, Examples

3.2 Adding up the two equivalent fractions. Add the two equivalent fractions which now have a common denominator. Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible: g ŌĆó 7 - (3) 7g - 3 ŌĆöŌĆöŌĆöŌĆöŌĆöŌĆöŌĆöŌĆöŌĆöŌĆöŌĆö = ŌĆöŌĆöŌĆöŌĆöŌĆöŌĆö 7 7 If you multiply binomials often enough you may notice a pattern. Notice that the first term in the result is the product of the first terms in each binomial. The second and third terms are the product of multiplying the two outer terms and then the two inner terms. And the last term results from multiplying the two last terms,. We abbreviate First, Outer, Inner, Last as FOIL (x - 3) Is a number, just 4, 10, 258, and so on. In the same way that 3^2 = 3 * 3, (x - 3)^2 = (x - 3) * (x-3), or (x - 3)(x-3). From there, we just multiply each term in the second set of parentheses by each term in the first set, and add these p.. Dividing exponential expressions : 5.1 x1 divided by x2 = x(1 - 2) = x(-1) = 1/x1 = 1/x Expand and Condense Logarithms DRAFT. 11 hours ago. by marialambert. Played 0 times. 0. 11th - 12th grade . Mathematics.

11) ŌłÆ(1 ŌłÆ 5x) 12) ŌłÆ4(7r + 7) -1- ┬®q 2KRubtnax ESzoBfetYw3aGrje n 3LZLECF.j X 6AkldlM SrLi5gWhdtqsZ FrheCsBetr PvHerdn.z R 5M7asd2eh rw CiXtxhT JIgnMfXiEn4iOtFeW ZAzlVgfeDbZrUa1 o13.c Worksheet by Kuta Software LL (Matching Type) Given f(x)=x+2 and g(x)=x2ŌłÆ4 match the expression to its simplification operation. x - 2 Answer 1 x2 + x - 2 Answer 2 1/x-2 Answer 3 -x2 + - 857 johnivansedotes johnivansedotes 3. Simplify the given function . Read the details on another example of addition on function in brainly.ph/question/1813217 Correct answer - Expand and simplify 3(2x + 1) + 2(x + 4) Step by step pl

In mathematics, function composition is an operation that takes two functions f and g and produces a function h such that h(x) = g(f(x)).In this operation, the function g is applied to the result of applying the function f to x.That is, the functions f : X ŌåÆ Y and g : Y ŌåÆ Z are composed to yield a function that maps x in X to g(f(x)) in Z.. Intuitively, if z is a function of y, and y is a. Textbook solution for Essential Calculus: Early Transcendentals 2nd Edition James Stewart Chapter T Problem 6ADT. We have step-by-step solutions for your textbooks written by Bartleby experts

### Solve 4(f+3)+3(f+3) Microsoft Math Solve

simplify g^ {4/7}*g^ {3/7} \square! \square! . Get step-by-step solutions from expert tutors as fast as 15-30 minutes. Your first 5 questions are on us QuickMath will automatically answer the most common problems in algebra, equations and calculus faced by high-school and college students. The algebra section allows you to expand, factor or simplify virtually any expression you choose. It also has commands for splitting fractions into partial fractions, combining several fractions into one and.

Expand 4(3. x. ŌłÆ 2) 4(3. x. ŌłÆ 2) = 12. x. ŌłÆ 8 Multiply everything inside the bracket by the 4 outside the bracket . Example 2 . Expand and simplify 3(x + 5) ŌłÆ 4(2. x + 3) 3(x + 5) ŌłÆ 4(2. x + 3) = 3. x + 15 ŌłÆ 8. x - 12 = 3 ŌłÆ 5. x. 1 . Expand each set of brackets separately by multiplying (x + 5) by 3 and (2. x + 3) by ŌłÆ4 . 2. e) 2├Ś3 f) 4 ├Ś5 g) ŌłÆ2├Ś7 h) 3├ŚŌłÆ2 i) 2 ├Ś j) 3 ├Ś2 k) ŌłÆ2 ├Ś l) ŌłÆ3 ├Ś4 m) ŌłÆ2 ├Ś(ŌłÆ ) n) ŌłÆ3 ├Ś o) ŌłÆ ├Ś(ŌłÆ2 ) p) 3 ├Ś(ŌłÆ2) q) (ŌłÆ ) r) (ŌłÆ2 ) s) 2 ├Ś t) ├Ś(ŌłÆ3 ) EXERCISE 2 Simplify the following: a) 2├Ś5 +3 ├Ś4 b) 5├Ś3 ŌłÆ2 ├Ś c) 3├Ś +2 ├Ś4 g) (2 G+1)( GŌłÆ5) h) (4 TŌłÆ7)(4 T+7) i) (3 T+2)2 j) (2 UŌłÆ7) 3. Multiply out and simplify :- a) ( UŌłÆ1)( U2+2 U+1) b) ( I+3)( I2+3 IŌłÆ2) c) ( T+3)( T2+ TŌłÆ2) d) ( PŌłÆ2)(3 P2ŌłÆ3 PŌłÆ2) e) ( TŌłÆ5)(2 T2+3 T+6) f) (2 G+3)(3 G2+4 GŌłÆ6) g) (5 I+3)2(3 IŌłÆ2) h) ( G2+4 G+1)2 i) (2 T2ŌłÆ6 TŌłÆ3)2 j) T( T+2)2 4. Expand the brackets and simplify. ŌłÆ3a 2(3ŌłÆb) = ŌłÆ9a 2+3a b Example Expand (x+5)x. Here, the brackets appear ’¼ürst, but the prin-ciple is the same. Both terms inside must be multiplied by the x outside: (x+5)x = x +5x Exercises 1. Remove the brackets from the following expressions. a) 5(x+4) b) 2(y ŌłÆ3) c) 4(3ŌłÆ a) d) x(2+x) e) p(q +3) f) ŌłÆ3(2+a) g) s(tŌłÆ s) h) ŌłÆ2(b.

### Given g(x)=5/(xŌłÆ3), evaluate and simplify: (g(5+h)ŌłÆg(5))/h

• 2.8) A sample of methane of mass 4.50 g occupies 12.7 L at 310 K. (a) Calculate the work done when the gas expands isothermally against a constant external pressure of 200 Torr until its volume has increased by 3.3 L. (b) Calculate the work tha
• A straight line passes through (0, 5) and (3, 17). (i)Find the equation of the line. A straight line has the equation y = 2(3 - 4x). Find the gradient and y-intercept of the line. ĒĀĄĒ▒Ü Index Laws. Simplify (i) ĒĀĄĒ▒Ø2├ŚĒĀĄĒ▒Ø7 (ii) 8 ├Ę 3 (iii) 4├Ś 3 5 (iv) 22 ├Ś3 3 4 (v) (ŌłÆ4)ŌłÆ2 Nth terms. Find the nth term and the 50th term of these sequences.
• In that case ŌłÆ3 ┬Ę -5 = +15 (a positive answer), but here is an example where the second part is negative: So the second term ended up negative because 2x ┬Ę ŌłÆa = ŌłÆ2ax, (it is also neater to write ŌłÆ2ax rather than ŌłÆ2xa). That was also interesting because of x being squared (x 2) Lastly, we have an example with three terms inside
• Solutions for Chapter 12 Problem 24STP: Choose the correct letter.Simplify (2x ŌłÆ 3)(5x + 4).F. 10x2 ŌłÆ 12G. 10x2 ŌłÆ 7x ŌłÆ 12H. 10x2 + 23x ŌłÆ 12I. 10x2 ŌłÆ 7x + 12 Get solutions Get solutions Get solutions done loading Looking for the textbook

16x 4 ŌłÆ 0.09818x 2 + 3.0593x ŌłÆ 23.77365 = 0. 5) A quartic equation solver to the rescue: Four roots were generated, two of which are imaginary. One root is negative and the fourth root (a positive value) is our answer for 'x.' It is 1.066 (rounded off). 6) Determine moles of H 2, then grams Coordinate Geometry 8 200 Negative gradients: m < 0 Positive gradients: m > 0 Chapter Contents 8:01 The distance between two points 8:02 The midpoint of an interval 8:03 The gradient of a line 8:04 Graphing straight lines 8:05 The gradient-intercept form of a straight line: y = mx + c Investigation: What does y = mx + c tell us? 8:06 The equation of a straight line, given poin Describe the transformation of f (x) = log 2 x represented by the graph of g. Question 6. Let f (x) = 2x 3 ŌłÆ 4x 2 + 8xŌłÆ 1, g (x) = 2x ŌłÆ 3x 4 ŌłÆ 6x 3 + 5, and h (x) = ŌłÆ7 + x 2 + x. Order the following functions from least degree to greatest degree. Question 7. Write an exponential model that represents each data set

Algebra (0th Edition) Edit edition. Problem 20E from Chapter 11.7: Expand and simplify the expression.(x ŌłÆ 1)4(x + 1)4. Get solution Factorise completely 7k2 ŌłÆ 22k + 3.  2. Expand and simplify (x + 2)(3x ŌłÆ 8) ŌłÆ 2x(y + 4) ŌłÆ 3y.  3. Write the area of the trapezium as both a factorised and expanded expression.  2m. Solve: Start with: S + A < 9. A = S + 3, so: S + (S + 3) < 9. Simplify: 2S + 3 < 9. Subtract 3 from both sides: 2S < 9 ŌłÆ 3. Simplify: 2S < 6. Divide both sides by 2: S < 3. Sam scored less than 3 goals, which means that Sam could have scored 0, 1 or 2 goals. Alex scored 3 more goals than Sam did, so Alex could have scored 3, 4, or 5 goals 18 x 3 y ŌłÆ3 x y ŌłÆ 36 x y 2 ŌłÆ3 x y 18 x 3 y ŌłÆ3 x y ŌłÆ 36 x y 2 ŌłÆ3 x y: Simplify. ŌłÆ6 x 2 + 12 y ŌłÆ6 x 2 + 12 y: Try It 5.75. Find the quotient: (32 a 2 b Use synthetic division to find the quotient and remainder when 4 x 3 + 5 x 2 ŌłÆ 5 x + 3 4 x 3 + 5 x 2. (a) y = x4 (b) g(s)=sŌłÆ2 (c) h(t)=t3/4 Example 3: Find the derivative of each of the following functions with respect to x: (a) y = 1 x5 (b) g(x)=3 ŌłÜ x (c) h(x)= 1 5 ŌłÜ x! The constant multiple rule: Let c be a constant andf(x) be a di’¼Ćerentiable function. ŌĆó (cf(x)) = c(f(x)). ŌĆó d dx! cf(x) = c d dx! f(x)

Page 5 (Section 4.1) 4.1 Homework Problems 1. Use a calculator to find each value to four decimal places. (a) 5 (b) 3 7 (c) ŽĆ 2ŌłÆ 5.3 (d) e2 (e) eŌłÆ2 (f) ŌłÆe 0.25 (g) ŽĆŌłÆ1 2. Simplify each expression without using a calculator Suppose that f(2) = ŌłÆ3, g(2) = 5, f '(2) = ŌłÆ2, and g'(2) = 4. Find h'(2)? h(x) = g(x) / 1 + f(x) Calculus Basic Differentiation Rules Chain Rul 2.2 Evaluate, Simplify, and Translate Expressions; 2.3 Solving Equations Using the Subtraction and Addition Properties of Equality; 2.4 Find Multiples and Factors; 2.5 Prime Factorization and the Least Common Multipl Convert the following integral to cylindrical coordinates and evaluate. ╦å 2 ŌłÆ2 ╦å ŌłÜ 4ŌłÆx2 ŌłÆ ŌłÜ 4ŌłÆx2 ╦å 16 (x2+y 2) 2 x 2 dz dy dx Textbook solution for Intermediate Algebra 10th Edition Jerome E. Kaufmann Chapter A Problem 19PE. We have step-by-step solutions for your textbooks written by Bartleby experts

Identify the asymptote of the function g(x) = 20.5x ŌłÆ 2. y=-2 Identify the transformed function that represents f(x) = ln x stretched vertically by a factor of 3, reflected across the x-axis, and shifted 7 units to the right e.g. 3 + x, 5y ŌłÆ 4x 2, x 2 ŌłÆ 3x + 5: coefficient: the number part of a particular term e.g. in the expression 5x 2 ŌłÆ x + 3, the coefficient of x 2 is 5 and the coefficient of x is -1: like terms: terms which have exactly the same letters in e.g. 2x and ŌłÆ3x are like terms, but 5y and 3y 2 are not like term Try to further simplify. Verificar expandir\:(2x-5)(3x+6) expandir\:(4x^2-3)(3x+1) expandir\:(x^2+3y)^3; expand-calculator. Expand ( x^{2}+3xŌłÆ4) ( x^{2}+5xŌłÆ1) pt. Related Symbolab blog posts. Middle School Math Solutions - Equation Calculator. Welcome to our new Getting Started math solutions series. Over the next few weeks, we'll. 2 x ┬▒ŌłÆ = M1 8.45, 3.55 A1 A1 20 (a) 2 3 ŌłÆ A1 (b) 2 2 1 1 5 x x ŌłÆ M1 15ŌłÆ x2 A1 (c) y 5 x y ŌłÆ = exchange letters, rearrange to y = M1 1 5 f() 1 x x ŌłÆ = ŌłÆ A1 ŌłÆ3 ŌłÆ2 ŌłÆ1 1 2 3 ŌłÆ2 2 4 6 8 10 12 14 x Exercise 2.5.1. Using the definition, determine whether the function f(x) = {2x + 1, if x < 1 2, if x = 1 ŌłÆ x + 4, if x > 1 is continuous at x = 1. If the function is not continuous at 1, indicate the condition for continuity at a point that fails to hold. Hint. Check each condition of the definition. Answer

The answer is (3x^2-3)*(2x^2 + 3x + 5) + (x^3 ŌłÆ 3x)*(4x+3), which simplifies to 10x^4+12x^3-3x^2-18x-15. According to the product rule, ( f Ōŗģ g ) ŌĆ▓ = f ŌĆ▓ Ōŗģ g + f Ōŗģ g ŌĆ▓ This just means that when you differentiate a product, you do derivative of the first, leave second alone, plus derivative of the second, leave the first alone. So the first would be (x^3 ŌłÆ 3x) and the second. Learn with Tiger how to do 0.25a^6b^2ŌłÆ0.6a^4b^4+0.36a^2b^6 fractions in a clear and easy way : Equivalent Fractions,Least Common Denominator, Reducing (Simplifying) Fractions Tiger Algebra Solve

1) Subtract the first equation from the second equation: 2C(s) + O 2 (g) + 4H 2 (g) ŌłÆ [2C(s) + O 2 (g)] ---> 2CH 3. 2) Simplify: 4H 2 (g) ---> 2CH 3. 3) Rearrange: 2CO(g) + 4H 2 (g) ---> 2CH 3. 4) Divide through by 2: CO(g) + 2H 2 (g) ---> CH 3. Solution #2: This is the usual way the ChemTeam uses to solve Hess' Law problems. 1) Do these. www.justmaths.co.uk Simplify / Expand & Simplify (F) - Version 3 January 2016 (d) ├¼6 ├¼2  12. To fill in a block, you must add the values on the two blocks directly below it 3.4.2 Recognize simple linear factors in a rational function. Next, we perform partial fraction decomposition on 3 x + 5 x 2 ŌłÆ 4 = 3 x + 5 (x + 2) (x Rewrite in terms of x and simplify. Substituting back into the original integral and simplifying gives

Double-Angle and Half-Angle Formulas. a 2 depend on which quadrant a 2 lies in. For cos. a 2 any formula can be used to solve for the exact value. ŽĆ 8. ŽĆ 8 is half of ŽĆ 4 and in the first quadrant. a = ŌłÆ 4 5 and 3 ŽĆ 2 Ōēż a < 2 ŽĆ. a, which would be 3 5 because a is in the 4 t h quadrant. 2 a for a from the previous problem 3.1 The Power Rule 57 Now without much trouble we can verify the formula for negative integers. First let's look at an example: EXAMPLE3.1.2 Find the derivative of y= xŌłÆ3.Using the formula, yŌĆ▓ = ŌłÆ3xŌłÆ3ŌłÆ1 = ŌłÆ3xŌłÆ4. Here is the general computation Math 145 Sec S08N01 - Final Exam Apr 21 2008 Question 4: (a)[5 points] Put the quadratic function f(x) = ŌłÆ2x2 ŌłÆ4xŌłÆ5 into standard form by completing the square. State the vertex and axis of symmetry of the graph of f(x) y=-x^2-x+6 expanded in the simplest form PREMISES y=(2-x)(3+x) in the expanded and simplified form CALCULATIONS y=(2-x)(3+x) in the expanded and simplified form y=(2├Ś3)+2x-3x-x^2 y=6+(2x-3x)-x^2 y=6+(-x)-x^2 y=6-x-x^2 [Flip the right side of the e.. This expression relates directly to the geometry of the rectangle-as-squares jigsaw as follows: 2 orange squares (16 x 16) ; 1 blue square (13 x 13) ; 4 red squares (3 x 3) ; 3 yellow squares (1 x 1) . Since the numbers always reduce, that is, the size of the remaining rectangle left over will always have one side smaller than the starting rectangle, then the process will always stop with a.